Puzzles riddles paradoxes #2

A right load of bollocks...

Re: Puzzles riddles paradoxes #2

Postby art0hur0moh » Wed Sep 22, 2021 6:47 pm

WombatDeath wrote:
art0hur0moh wrote:(1+3 *4)*2=24
woo hoo

You're slightly out with that one, which equals 26. But you only need to alter one symbol to get the right answer.

.SF. wrote:b) (5+3-2)*4=24

Yep!

3*4=12+1=13*4= 52 :gigglesnshit: 13*2

Here, what is it with having a value but the second it is multiplied by 0 the original value is negligible? Not found an answer to that in 30 years?
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Re: Puzzles riddles paradoxes #2

Postby art0hur0moh » Wed Sep 22, 2021 7:01 pm

1, 3, 4, 6
Text using multiplication gave me the idea, if knowing the total value, it might be easier to see how to back track to correct answer? And where are my pens and pencils?

1*3=3*4=12*6=72? not helpful in the slightest :pmsl:
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Re: Puzzles riddles paradoxes #2

Postby .SF. » Thu Sep 23, 2021 9:12 am

WombatDeath wrote:
.SF. wrote:
WombatDeath wrote:Hah, very good! But yes, I'm afraid that that falls squarely under the "funny business" umbrella.

For what it's worth, you're thinking in the right sort of direction with the start of your solution.


So I don't go charging down the wrong path can I check that your clue means try dividing six by something other than a whole number?

Correct!


I'm not there yet. My thinking so far is:

Spoiler: show
need to divide 6 by a fraction made from some combination of 1,3,4
the fractions I come up with are 1/3, 1/4, 3/4, 4/3, 2/4, 3/5, 5/3
dividing 6 by:
1/3 gives 18 with a 4 left over making 22 - no good
1/4 gives 24 which looks promising but there's still a spare 3 floating around
3/4 gives 8 with a 1 left over which gets me nowhere
4/3 gives 4.5 and a spare 1 - useless
2/4 gives 12 and a spare 3 - just as useless
3/5 gives 10 and a spare 4 - forget it
5/3 - no way.

So if this one really is solvable the answer must come from one of the above options but I can't see which. I think I'm missing something here.
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Re: Puzzles riddles paradoxes #2

Postby WombatDeath » Thu Sep 23, 2021 12:56 pm

.SF. wrote:
WombatDeath wrote:
.SF. wrote:
WombatDeath wrote:Hah, very good! But yes, I'm afraid that that falls squarely under the "funny business" umbrella.

For what it's worth, you're thinking in the right sort of direction with the start of your solution.


So I don't go charging down the wrong path can I check that your clue means try dividing six by something other than a whole number?

Correct!


I'm not there yet. My thinking so far is:

Spoiler: show
need to divide 6 by a fraction made from some combination of 1,3,4
the fractions I come up with are 1/3, 1/4, 3/4, 4/3, 2/4, 3/5, 5/3
dividing 6 by:
1/3 gives 18 with a 4 left over making 22 - no good
1/4 gives 24 which looks promising but there's still a spare 3 floating around
3/4 gives 8 with a 1 left over which gets me nowhere
4/3 gives 4.5 and a spare 1 - useless
2/4 gives 12 and a spare 3 - just as useless
3/5 gives 10 and a spare 4 - forget it
5/3 - no way.

So if this one really is solvable the answer must come from one of the above options but I can't see which. I think I'm missing something here.

That's right, the answer does come from one of your listed options, but there is a way in which you can assemble your fraction without having a stray digit left over. As a hint, here is the order of the digits:

Spoiler: show
6 / (1 3 4)
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Re: Puzzles riddles paradoxes #2

Postby Text » Thu Sep 23, 2021 1:55 pm

WombatDeath wrote:
That's right, the answer does come from one of your listed options, but there is a way in which you can assemble your fraction without having a stray digit left over. As a hint, here is the order of the digits:
Spoiler: show
6 / (1 3 4)

Hmm no funny business, you said. *wags finger* :ooer:

The first three equations are quite easy, the other two seem impossibly hard. No middle ground!
Couldn't make any headway - gave up after half an hour (that was 3 days ago).
I'm quite content to sit back now & wait until SF solves it - or until you show us the answer. No rush! :leer:
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Re: Puzzles riddles paradoxes #2

Postby Taschenrechner » Thu Sep 23, 2021 3:29 pm

WombatDeath wrote:
.SF. wrote:

I'm not there yet. My thinking so far is:

Spoiler: show
need to divide 6 by a fraction made from some combination of 1,3,4
the fractions I come up with are 1/3, 1/4, 3/4, 4/3, 2/4, 3/5, 5/3
dividing 6 by:
1/3 gives 18 with a 4 left over making 22 - no good
1/4 gives 24 which looks promising but there's still a spare 3 floating around
3/4 gives 8 with a 1 left over which gets me nowhere
4/3 gives 4.5 and a spare 1 - useless
2/4 gives 12 and a spare 3 - just as useless
3/5 gives 10 and a spare 4 - forget it
5/3 - no way.

So if this one really is solvable the answer must come from one of the above options but I can't see which. I think I'm missing something here.

That's right, the answer does come from one of your listed options, but there is a way in which you can assemble your fraction without having a stray digit left over. As a hint, here is the order of the digits:

Spoiler: show
6 / (1 3 4)



If I've got this right, the (1?3?4) has to equal 1/4, then 6 divided by 1/4 = 24
The only solution I can see is,

(6/(1^3,divided by 4) which does equal 24, but I think you'll rule that out as "funny business". :bawlin: :laughing:


3 3 7 7

The closest I can get is 3+(3x7) =24, but obviously that's missing a 7, or (3x3)+7+7= 23, which is just as obviously 1 short
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Re: Puzzles riddles paradoxes #2

Postby .SF. » Thu Sep 23, 2021 3:42 pm

Taschenrechner wrote:
WombatDeath wrote:
.SF. wrote:

I'm not there yet. My thinking so far is:

Spoiler: show
need to divide 6 by a fraction made from some combination of 1,3,4
the fractions I come up with are 1/3, 1/4, 3/4, 4/3, 2/4, 3/5, 5/3
dividing 6 by:
1/3 gives 18 with a 4 left over making 22 - no good
1/4 gives 24 which looks promising but there's still a spare 3 floating around
3/4 gives 8 with a 1 left over which gets me nowhere
4/3 gives 4.5 and a spare 1 - useless
2/4 gives 12 and a spare 3 - just as useless
3/5 gives 10 and a spare 4 - forget it
5/3 - no way.

So if this one really is solvable the answer must come from one of the above options but I can't see which. I think I'm missing something here.

That's right, the answer does come from one of your listed options, but there is a way in which you can assemble your fraction without having a stray digit left over. As a hint, here is the order of the digits:

Spoiler: show
6 / (1 3 4)



If I've got this right, the (1?3?4) has to equal 1/4, then 6 divided by 1/4 = 24
The only solution I can see is,(6/(1^3,divided by 4) which does equal 24, but I think you'll rule that out as "funny business". :bawlin: :laughing:


After a lot of head scratching and spurred on by Wombat's handy hints I've finally come up with

Spoiler: show
6/(1-(¾))
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Re: Puzzles riddles paradoxes #2

Postby WombatDeath » Thu Sep 23, 2021 5:37 pm

Yes, well done!
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Re: Puzzles riddles paradoxes #2

Postby art0hur0moh » Thu Sep 23, 2021 7:40 pm

reminds me of transposition. But had to do a bit further investigation online.
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Re: Puzzles riddles paradoxes #2

Postby WombatDeath » Thu Sep 23, 2021 8:38 pm

Taschenrechner wrote:3 3 7 7

The closest I can get is 3+(3x7) =24, but obviously that's missing a 7, or (3x3)+7+7= 23, which is just as obviously 1 short


Yes, the last one is particularly nasty. I'll give a hint tomorrow if nobody gets it in the meantime.
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Re: Puzzles riddles paradoxes #2

Postby .SF. » Fri Sep 24, 2021 8:23 am

WombatDeath wrote:
Taschenrechner wrote:3 3 7 7

The closest I can get is 3+(3x7) =24, but obviously that's missing a 7, or (3x3)+7+7= 23, which is just as obviously 1 short


Yes, the last one is particularly nasty. I'll give a hint tomorrow if nobody gets it in the meantime.


If the previous one was anything to go by I'm guessing this one also involves fiddling around with fractions.
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Re: Puzzles riddles paradoxes #2

Postby Text » Fri Sep 24, 2021 12:06 pm

.SF. wrote:
WombatDeath wrote:
Taschenrechner wrote:3 3 7 7

The closest I can get is 3+(3x7) =24, but obviously that's missing a 7, or (3x3)+7+7= 23, which is just as obviously 1 short


Yes, the last one is particularly nasty. I'll give a hint tomorrow if nobody gets it in the meantime.



If the previous one was anything to go by I'm guessing this one also involves fiddling around with fractions.

We know that all those puzzles can be solved. If they were unsolvable he wouldn't have posted them. But gawd, they're tough ! :thud:
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Re: Puzzles riddles paradoxes #2

Postby .SF. » Fri Sep 24, 2021 3:48 pm

After a struggle I finally got there

Spoiler: show
7*(3+(3/7))
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Re: Puzzles riddles paradoxes #2

Postby WombatDeath » Fri Sep 24, 2021 8:13 pm

.SF. wrote:After a struggle I finally got there

Spoiler: show
7*(3+(3/7))

Wow, I thought I was going to have to give at least one hint, and even then I wasn't sure anyone would get it. Well done!
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Re: Puzzles riddles paradoxes #2

Postby .SF. » Fri Sep 24, 2021 9:10 pm

WombatDeath wrote:
.SF. wrote:After a struggle I finally got there

Spoiler: show
7*(3+(3/7))

Wow, I thought I was going to have to give at least one hint, and even then I wasn't sure anyone would get it. Well done!


I'm not going to let you get away with this. Having made us suffer I'm throwing down the gauntlet - here's one of my own making for you (or anyone else) to have a go at = 24's the target like before and same rules apply.

2,2,7,14
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