WombatDeath wrote:.SF. wrote:I'm not there yet. My thinking so far is:

need to divide 6 by a fraction made from some combination of 1,3,4

the fractions I come up with are 1/3, 1/4, 3/4, 4/3, 2/4, 3/5, 5/3

dividing 6 by:

1/3 gives 18 with a 4 left over making 22 - no good

1/4 gives 24 which looks promising but there's still a spare 3 floating around

3/4 gives 8 with a 1 left over which gets me nowhere

4/3 gives 4.5 and a spare 1 - useless

2/4 gives 12 and a spare 3 - just as useless

3/5 gives 10 and a spare 4 - forget it

5/3 - no way.

So if this one really is solvable the answer must come from one of the above options but I can't see which. I think I'm missing something here.

That's right, the answer does come from one of your listed options, but there is a way in which you can assemble your fraction without having a stray digit left over. As a hint, here is the order of the digits:

If I've got this right, the (1?3?4) has to equal 1/4, then 6 divided by 1/4 = 24

The only solution I can see is,

(6/(1^3,divided by 4) which does equal 24, but I think you'll rule that out as "funny business".

3 3 7 7

The closest I can get is 3+(3x7) =24, but obviously that's missing a 7, or (3x3)+7+7= 23, which is just as obviously 1 short